In each of the following cases, state whether the function is one-one, onto or bijective. Justify your answer. (i) f : R → R defined by f(x) = 3 – 4x (ii) f : R → R defined by f(x) = 1 + x^2
Class 12, NCERT Chapter 1, Exercise 1.2, Q7 (i) Here f(x) = 3 – 4x Then f(x 1 ) = 3 – 4x 1 and f (x 2 ) = 3 – 4x 2 Now f(x 1 ) = f (x 2 ) ⇒ 3 – 4x 1 = 3 – 4x 2 ⇒ – 4x 1 = –4x 2 ⇒ x 1 = x 2 ∴ f(x 1 ) = f(x 2 ) & x 1 = x 2 So, f is one-one function. Let f(x) = y ∈ R Then y=3 - 4x ⇒ x= 3-y/4 (ii) Let x 1 = 2 and x 2 = –2 ∈ R Here f(x) = 1 + x 2 Then f(x 1 ) = f (2) = 1 + (2) 2 = 5 and f (x 2 ) = f(–2) = 1 + (–2) 2 = 5 ∴ f (x 1 ) = f(x 2 ) but x 1 ≠ x 2 So, f is not one-one function. Let f(x) = – 2 ⇒R Then 1 + x 2 = –2 ⇒ x 2 = –3 = ± √–3 ∈R So, f is not onto function.
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