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Fast 9 | F9 | Fast and Furious 9| All fast movies download

Fast 9 | F9 | Fast and Furious 9| All fast movies HD download free

It is one of the best Hollywood movie in the world. Fast & Furious 9 is an upcoming American action film directed by Justin Lin and written by Daniel Casey. It will be the ninth installment in The Fast and the Furious franchise.Little is known about the next Fast & Furious film but we know it will unite the Toretto family once again with Mia's return to the fold.


Also, could Cena be playing the film's antagonist - the silence on his role might suggest he will go toe to toe with Dom - which we would love to see!

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Let L be the set of all lines in a plane and R be the relation in L defined as R = {(L1 , L2 ) : L1 is perpendicular to L2 }. Show that R is symmetric but neither reflexive nor transitive.

RELATIONS AND FUNCTIONS Class 12, NCERT Chapter 1,  Example 3 Solution Figure R is not reflexive, as a line L1 can not be perpendicular to itself, i.e., (L1 , L1 ) ∉ R. R is symmetric as (L1 , L2 ) ∈ R ⇒ L1 is perpendicular to L2 ⇒ L2 is perpendicular to L1 ⇒ (L2 , L1 ) ∈ R. R is not transitive. Indeed, if L1 is perpendicular to L2 and L2 is perpendicular to L3 , then L1 can never be perpendicular to L3 . In fact, L1 is parallel to L3 , i.e., (L1 , L2 ) ∈ R, (L2 , L3 ) ∈ R but (L1 , L3 ) ∉ R. Example1       Example2 Example3 ←you are here

Let A = R – {3} and B = R – {1}. Consider the function f : A → B defined by f(x) = (x-2)/(x-3) Is f one-one and onto? Justify your answer.

Class 12, NCERT Chapter 1,  Exercise 1.2, Q10 A =  R  - {3}, B =  R  - {1} f : A → B is defined as Let x,y∈A such that f(x)=f(y). ⇒ (x-2)/(x-3)=(y-2)/(y-3) ⇒ (x-2)(y-3)=(y-2)(x-3) ⇒ xy-3x-2y+6=xy-3y-2x+6 ⇒ -3x-2y=-3y-2x ⇒ 3x-2x=3y-2y ⇒ x=y ∴  f  is one-one. Let  y  ∈B =  R  - {1}. Then,  y  ≠ 1. The function  f  is onto if there exists  x  ∈A such that  f ( x ) =  y. Now, f(x)=y ⇒(x-2)(x-3)=y ⇒x-2=xy-3y ⇒x(1-y)=-3y+2 ⇒ x=2-3y/1-y  ∈A   Thus, for any  y  ∈ B, there exists  x=2-3y/1-y  ∈A     such that Hence, function  f  is one-one and onto.

Prove that the function f : R → R, given by f(x) = 2x, is one-one and onto.

Class 12, NCERT Chapter 1,  Example10  f is one-one, as  f ( x 1 ) = f ( x 2 ) ⇒  2 x 1 = 2 x 2  ⇒ x 1 = x 2 Also, given any real number y in R,  there exists y/2 in R,  such that  f( y/2 ) = 2 . ( y/2 ) = y.  Hence, f is onto